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How do you solve the system?: $x + 3y = –4$ , $2x + 2y = –8$ ?

1 Answer

Oct 22, 2015

$(x,y) = (-4,0)$

Explanation:

Given:
[1] $color(white)("XXX")x+3y=-4$
[2] $color(white)("XXX")2x+2y=-8$

Multiply [1] by $2$
[3] $color(white)("XXX")2x+6y=-8$

Subtract[2] from [3]
[4] $color(white)("XXX")4y=0$

Divide [4] by $4$
[5] $color(white)("XXX")y=0$

Substitute $0$ for $y$ in [1]
[6] $color(white)("XXX")x+3(0)=-4$

Simplify
[7] $color(white)("XXX")x=-4$

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