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How do you solve the system?: #x + 3y = –4#, #2x + 2y = –8#?

1 Answer

Oct 22, 2015

#(x,y) = (-4,0)#

Explanation:

Given:
[1]#color(white)("XXX")x+3y=-4#
[2]#color(white)("XXX")2x+2y=-8#

Multiply [1] by #2#
[3]#color(white)("XXX")2x+6y=-8#

Subtract[2] from [3]
[4]#color(white)("XXX")4y=0#

Divide [4] by #4#
[5]#color(white)("XXX")y=0#

Substitute #0# for #y# in [1]
[6]#color(white)("XXX")x+3(0)=-4#

Simplify
[7]#color(white)("XXX")x=-4#

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