How do you solve 3x + 2y = 4 and 2x + y = 3?

1 Answer
Mar 17, 2017

See the entire solution process below:

Explanation:

Step 1) Solve the second equation for y:

2x + y = 3

2x + y - color(red)(2x) = 3 - color(red)(2x)

2x - color(red)(2x) + y = 3 - 2x

0 + y = 3 - 2x

y = 3 - 2x

Step 2) Substitute 3 - 2x for y in the first equation and solve for x:

3x + 2y = 4 becomes:

3x + 2(3 - 2x) = 4

3x + (2 xx 3) - (2 xx 2x) = 4

3x + 6 - 4x = 4

3x - 4x + 6 = 4

(3 - 4)x + 6 = 4

-1x + 6 = 4

-x + 6 - color(red)(6) = 4 - color(red)(6)

-x + 0 = -2

-x = -2

color(red)(-1) xx -x = color(red)(-1) xx -2

x = 2

Step 3) Substitute 2 for x in the solution to the second equation at the end of Step 1 and calculate y:

y = 3 - 2x becomes:

y = 3 - (2 xx 2)

y = 3 - 4

y = -1

The solution is x = 2 and y = -1 or (2, -1)