How do you solve the system of equations $\frac { 2} { 3} x - \frac { 1} { 2} y = 3$ and $\frac { 1} { 3} x - \frac { 1} { 4} y = \frac { 3} { 2}$ ?

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Answer 1 · 2017-11-19T11:46:19

$x=(18+3y)/4$
OR
$y=(4x-18)/3$

$2/3x-1/2y=3$
$1/3x-1/4y=3/2$

$=>$

$6*(2/3x-1/2y)=6*(3)$
$12*(1/3x-1/4y)=12*(3/2)$

$=>$

$4x-3y=18$
$4x-3y=18$

$=>$

$4x-3y=18$

$=>$

$x=(18+3y)/4$
OR
$y=(4x-18)/3$

How do you solve the system of equations \frac { 2} { 3} x - \frac { 1} { 2} y = 3\frac { 2} { 3} x - \frac { 1} { 2} y = 3 and \frac { 1} { 3} x - \frac { 1} { 4} y = \frac { 3} { 2}\frac { 1} { 3} x - \frac { 1} { 4} y = \frac { 3} { 2}?