How do you solve y-2x=6 and x+4y=15?

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Answer 1 · 2018-03-02T20:26:28

#x=-1# & #y=4#

Equation 1:

#y-2x=6#

#color(red)(-2x+y=6)# [Rearranging]

Equation 2:

#x+4y=15#

#color(magenta)(2x+8y=30)# [Multiplying by 2]

Adding Equation 1 & Equation 2:

#9y=36#

#y=36/9#

#color(green)(y=4)#

Substituting y=4 in Equation 1:

#y-2x=6#

#4-2x=6#

#-2x=6-4=-2#

#color(orange)(x=-2/2=-1)#

Therefore, #x=-1# & #y=4#

~Hope this helps! :)