How do you solve the following system?: x=-3y -6, -x-8y=32

1 Answer
Dec 3, 2015

This set of equation has one solution:

{(x=-20 2/5),(y=-4 4/5):}

Explanation:

{(x=-3y-6),(-x-8y=32):}

First I ordered both equations by placing the variables on the left side and free terms on the right side.

{(x+3y=-6),(-x-8y=32):}

We can see that variable x has opposite coefficients so if I add both equations I get equation with one unknown:

-5y=24

y=-24/5=-4 4/5

Now I substitute calculated x to the first equation:

x=-3*(-24/5)-6

x=-72/5-6

x=-72/5-30/5

x=-102/5=-20 2/5