How do you solve the following system?: $x = - 3 y - 6, - x - 8 y = 32$ $x=-3y -6, -x-8y=32$

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Answer 1 · 2015-12-03T10:47:41

This set of equation has one solution:

${(x=-20 2/5),(y=-4 4/5):}$

${(x=-3y-6),(-x-8y=32):}$

First I ordered both equations by placing the variables on the left side and free terms on the right side.

${(x+3y=-6),(-x-8y=32):}$

We can see that variable $x$ has opposite coefficients so if I add both equations I get equation with one unknown:

$-5y=24$

$y=-24/5=-4 4/5$

Now I substitute calculated $x$ to the first equation:

$x=-3*(-24/5)-6$

$x=-72/5-6$

$x=-72/5-30/5$

$x=-102/5=-20 2/5$

How do you solve the following system?: x=-3y -6, -x-8y=32 x=−3y−6,−x−8y=32 x=-3y -6, -x-8y=32