How do you solve $x = - 5 + 2 y$ $x = -5 + 2y$ and $2 x + 3 y = 4$ $2x + 3y = 4$ using substitution?

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How do you solve $x = - 5 + 2 y$ $x = -5 + 2y$ and $2 x + 3 y = 4$ $2x + 3y = 4$ using substitution?

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Answer 1 · 2016-08-05T12:05:26

To solve, substitute the $x$ $x$ in the second equation for the $x$ $x$ in the first equation.

Explanation:

The first equation is already solved for $x$ $x$ , so let's put that equation into the second equation. It'll look like this:

$2 (- 5 + 2 y) + 3 y = 4$ $2(-5+2y)+3y=4$

Next, use the distributive property to simplify our equation:

$- 10 + 4 y + 3 y = 4$ $-10+4y+3y=4$

Now, let's combine $3 y$ $3y$ and $4 y$ $4y$ to make $7 y$ $7y$ :

$- 10 + 7 y = 4$ $-10+7y=4$

Next, add $10$ $10$ to each side:

$7 y = 14$ $7y=14$

The final step in solving for y is to divide each side by $7$ $7$ :

$y = 2$ $y=2$

We've now solved for y. Now, we have to solve for x. The easiest way to do this is to substitute our y-value into the first equation, since it's already solved for x:

$x = - 5 + 2 (2)$ $x=-5+2(2)$

$x = - 5 + 4$ $x=-5+4$

$x = - 1$ $x=-1$

Using our x and y value and combining them to get an ordered pair, we now have our answer: $(- 1, 2)$ $(-1,2)$

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How do you solve $x = - 5 + 2 y$ $x = -5 + 2y$ and $2 x + 3 y = 4$ $2x + 3y = 4$ using substitution?

1 Answer

Explanation:

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How do you solve x = -5 + 2yx=−5+2yx = -5 + 2y and 2x + 3y = 42x+3y=42x + 3y = 4 using substitution?

1 Answer

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How do you solve $x = - 5 + 2 y$ $x = -5 + 2y$ and $2 x + 3 y = 4$ $2x + 3y = 4$ using substitution?