How do you solve the following system?: x +2y =5, -4x +y = -3x+2y=5,4x+y=3

1 Answer
Jun 29, 2018

See a solution process below:

Explanation:

Step 1) Solve the first equation for xx:

x + 2y = 5x+2y=5

x + 2y - color(red)(2y) = 5 - color(red)(2y)x+2y2y=52y

x + 0 = 5 - 2yx+0=52y

x = 5 - 2yx=52y

Step 2) Substitute (5 - 2y)(52y) for xx in the second equation and solve for yy:

-4x + y = -34x+y=3 becomes:

-4(5 - 2y) + y = -34(52y)+y=3

(-4 xx 5) - (-4 xx 2y) + y = -3(4×5)(4×2y)+y=3

-20 - (-8y) + y = -320(8y)+y=3

-20 + 8y + y = -320+8y+y=3

-20 + 8y + 1y = -320+8y+1y=3

-20 + (8 + 1)y = -320+(8+1)y=3

-20 + 9y = -320+9y=3

-20 + color(red)(20) + 9y = -3 + color(red)(20)20+20+9y=3+20

0 + 9y = 170+9y=17

9y = 179y=17

(9y)/color(red)(9) = 17/color(red)(9)9y9=179

(color(red)(cancel(color(black)(9)))y)/cancel(color(red)(9)) = 17/9

y = 17/9

Step 3) Substitute 17/9 for y in the solution to the first equation at the end of Step 1 and calculate x:

x = 5 - 2y becomes:

x = 5 - (2 xx 17/9)

x = 5 - 34/9

x = (9/9 xx 5) - 34/9

x = 45/9 - 34/9

x = (45 - 34)/9

x = 11/9

The Solution Is:

x = 11/9 and y = 17/9

Or

(11/9, 17/9)