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How do you solve the following system: #4x-2y=4 , 4x-5y-23=0 #?

1 Answer

Jun 14, 2017

#x = -13/6 and y = -19/3#

Explanation:

Write both equations with #4x# as the subject.

#4x = 2y+4" and "4x = 5y +23#

#color(white)(xxxxxxxx)4x = 4x#

#color(white)(xxxxx)5y +23 = 2y+4#

#color(white)(xxxxx)5y -2y = 4-23#

#color(white)(xxxxxxxx)3y = -19#

#color(white)(xxxxxxxxx)y = -19/3#
#4x= (2y+4)#

#x = (2y+4)/4#

#x = (2((-19)/3) +4)div 4#

#x = -13/6#

Check:

#4x = 5y+23#

#4xx(-13)/6 = 5((-19)/3)+23#

#-26/3 = -26/3#

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