How do you solve the following system: 4x-2y=4 , 4x-5y-23=0 ? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer EZ as pi Jun 14, 2017 x = -13/6 and y = -19/3 Explanation: Write both equations with 4x as the subject. 4x = 2y+4" and "4x = 5y +23 color(white)(xxxxxxxx)4x = 4x color(white)(xxxxx)5y +23 = 2y+4 color(white)(xxxxx)5y -2y = 4-23 color(white)(xxxxxxxx)3y = -19 color(white)(xxxxxxxxx)y = -19/3 4x= (2y+4) x = (2y+4)/4 x = (2((-19)/3) +4)div 4 x = -13/6 Check: 4x = 5y+23 4xx(-13)/6 = 5((-19)/3)+23 -26/3 = -26/3 Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve y=-6x-3 and y=3 using the substitution method? How do you solve 12y-3x=-1 and x-4y=1 using the substitution method? Which method do you use to solve the system of equations y=1/4x-14 and y=19/8x+7? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve x+y=5 and 3x+y=15 using the substitution method? What is the point of intersection of the lines x+2y=4 and -x-3y=-7? See all questions in Systems Using Substitution Impact of this question 1097 views around the world You can reuse this answer Creative Commons License