How do you solve $3/x +2/y = - 5/6$ and $1/x - 1/y = -5/6$ using substitution?

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Answer 1 · 2018-01-09T16:17:11

$x=-2$ and $y=3$

As $1/x-1/y=-5/6$ , we have $1/x=1/y-5/6$

substituting $1/x$ in first equation we get

$3(1/y-5/6)+2/y=-5/6$

or $3/y-15/6+2/y=-5/6$

or $5/y=10/6$

or $10y=30$ and $y=3$

Hence $1/x=1/3-5/6=(2-5)/6=-3/6=-1/2$

i.e. $x=-2$

How do you solve 3/x +2/y = - 5/63/x +2/y = - 5/6 and 1/x - 1/y = -5/61/x - 1/y = -5/6 using substitution?