How do you solve $-6y - 2x = 0$ and $11y + 3x = 4$ using substitution?

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Answer 1 · 2017-01-05T21:46:04

$x=-6 and y=2$

$-6y -2x =0 to -6y = 2x$
Therefore $-3y = x$

We can substitute $color(blue)(-3y = x)$ into the second equation;

$11y + 3 color(red)((x)) = 4$
$11y + 3 color(red)((-3y)) = 4$

This is simplified to;

$11y -9y =4$
$2y=4$
$y=2$

As we know that $color(blue)(-3y = x)$ , we can substitute the value of $y$ into that to get $x$

$-3y = x to -3(2) =x$

$-6=x$

How do you solve -6y - 2x = 0-6y - 2x = 0 and 11y + 3x = 411y + 3x = 4 using substitution?