How do you solve the system 0.5x+4y=-10.5x+4y=1 and x+2.5y=3.5x+2.5y=3.5 using substitution?

1 Answer
Jul 26, 2017

See a solution process below:

Explanation:

Step 1) Solve the first equation for xx:

0.5x + 4y = -10.5x+4y=1

0.5x + 4y - color(red)(4y) = -1 - color(red)(4y)0.5x+4y4y=14y

0.5x + 0 = -1 - 4y0.5x+0=14y

color(red)(2) xx 0.5x = color(red)(2)(-1 - 4y)2×0.5x=2(14y)

1x = (color(red)(2) xx -1) - (color(red)(2) xx 4y)1x=(2×1)(2×4y)

x = -2 - 8yx=28y

Step 2) Substitute (-2 - 8y)(28y) for xx in the second equation and solve for yy:

x + 2.5y = 3.5x+2.5y=3.5 becomes:

(-2 - 8y) + 2.5y = 3.5(28y)+2.5y=3.5

-2 - 8y + 2.5y = 3.528y+2.5y=3.5

color(red)(2) - 2 - 8y + 2.5y = color(red)(2) + 3.5228y+2.5y=2+3.5

0 - 8y + 2.5y = 5.508y+2.5y=5.5

-8y + 2.5y = 5.58y+2.5y=5.5

(-8 + 2.5)y = 5.5(8+2.5)y=5.5

-5.5y = 5.55.5y=5.5

(-5.5y)/color(red)(-5.5) = 5.5/color(red)(-5.5)5.5y5.5=5.55.5

(color(red)(cancel(color(black)(-5.5)))y)/cancel(color(red)(-5.5)) = -1

y = -1

Step 3)* Substitute -1 for y in the solution to the first equation at the end of Step 1 and calculate x:

x = -2 - 8y becomes:

x = -2 - (8 * -1)

x = -2 - (-8)

x = -2 + 8

x = 6

The Solution Is: x = 6 and y = -1 or (6, -1)