How do you solve the system y=-x+2 and y=x-4?
1 Answer
Mar 2, 2018
Explanation:
y=-x+2to(1)
y=x-4to(2)
"adding "(1)" and "(2)" will eliminate term in x"
"adding term by term on both sides"
(y+y)=(-x+x)+(2-4)
rArr2y=-2
"divide both sides by 2"
(cancel(2) y)/cancel(2)=(-2)/2
rArry=-1
"substitute this value into either equation "(1)" or "(2)
"substituting in equation "(2)" gives"
-1=x-4rArrx=-1+4=3
"point of intersection "=(3,-1)
graph{(y+x-2)(y-x+4)((x-3)^2+(y+1)^2-0.04)=0 [-10, 10, -5, 5]}
