How do you solve $2 x + y = 7$ $2x + y = 7$ and $y - x = 1$ $y - x = 1$ using substitution?

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How do you solve $2 x + y = 7$ $2x + y = 7$ and $y - x = 1$ $y - x = 1$ using substitution?

2 Answers

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Answer 1 · 2018-03-08T16:57:51

$therefore$ $color(darkred)(x=2 and y=3$

Explanation:

$2x+y=7$

$y=7-2x$

Given that,

$y-x=1$

Substituting $y=7-2x$

$7-2x-x=1$

$7-3x=1$

$-3x=1-7$

$-3x=-6$

$x=(-6)/-3$

$color(magenta)(x=2$

$y=7-2x$

$y=7-2xx2$

$y=7-4$

$color(magenta)(y=3$

$therefore$ $color(darkred)(x=2 and y=3$

~Hope this helps! :)

Answer 2 · 2018-03-08T17:59:52

$y=3,x=2$

Explanation:

$2x+y=7------(1)$
$-x+y=1--------(2)$

$(1)-(2)$

$3x=6$

$x=6/3$

$x=2$

substitute $x=2$ in $(2)$

$:.-(2)+y=1$

$:.y=1+2$

$:.y=3$
~~~~~~~~~~~
check:-

substitute $y=3 and x=2$ in (1)

$:.2(2)+(3)=7$

$:.4+3=7$

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How do you solve $2 x + y = 7$ $2x + y = 7$ and $y - x = 1$ $y - x = 1$ using substitution?

2 Answers

Explanation:

Explanation:

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How do you solve $2 x + y = 7$ $2x + y = 7$ and $y - x = 1$ $y - x = 1$ using substitution?