How do you solve the system of equations: 3T-2S=0, T+2S=15?

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Answer 1 · 2015-08-22T08:01:40

The solutions are
$color(blue)(T=3.75, S=5.625$

$3T-color(blue)(2S)=0$
$T+color(blue)(2S)=15$

Solving by elimination

Adding both equations
$3T-cancelcolor(blue)(2S)=0$

$T+cancelcolor(blue)(2S)=15$
$4T=15$
$T=15/4$
$color(blue)(T=3.75$

Finding $S$ from equation $1$
$3T-2S=0$

$3T=2S$

$S=(3T)/2$

$S=11.25/2$
$color(blue)(S=5.625$