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How do you find the point of intersection for #x+3y=12# and #x-y=4#?

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1 Answer

Jul 1, 2015

The point of intersection occurs at #(x,y) = (6,2)#

Explanation:

[1]#color(white)("XXXX")##x+3y=12#
[2]#color(white)("XXXX")##x-y = 4#

Subtract [2] from [1] to remove the variable #x# from the equation
[3]#color(white)("XXXX")#4y = 8#

Divide both sides of [3] by #4#
[4]#color(white)("XXXX")##y = 2#

Substitute #y=2# in [1]
[5]#color(white)("XXXX")##x+3(2) = 12#

Simplifying
[6]#color(white)("XXXX")##x = 6#

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