How do you solve the following system?: $x+3y-z=14, 7x+6y+z=1, 4x-2y-5z=11$

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Answer 1 · 2017-07-16T01:33:27

$x=-2.7$
$y=3.598$
$z=-5.38$

Given -

$x+3y-z=14$ -------------------------(1)
$7x+6y+z=1$ -------------------------(2)
$4x-2y-5z=11$ --------------------(3)

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Solution is offered from the template I created in MS Excell

$x=-2.7$
$y=3.598$
$z=-5.38$

How do you solve the following system?: x+3y-z=14, 7x+6y+z=1, 4x-2y-5z=11 x+3y-z=14, 7x+6y+z=1, 4x-2y-5z=11