How do you solve #x^2 - 2y = 1# & #x^2 + 5y = 29#?
1 Answer
Jun 19, 2018
x=pm3,y=4#
Explanation:
Multiplying the first equation by
so
plugging this in the first equation we get
x=pm3,y=4#
Multiplying the first equation by
so
plugging this in the first equation we get