How do you solve the following system?: $x - 9 y = 15, x - 2 y = - 5$ $x -9y =15, x -2y = -5$

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Answer 1 · 2018-07-02T19:25:07

$x = - \frac{20}{7}$ $x=-20/7$ , $y = - \frac{75}{7}$ $y=-75/7$

System of linear equations,

$x-9y=15\ .......(1)$

$x-2y=-5\ .......(2)$

Subtracting (2) from (1) we get

$x-9y-(x-2y)=15-(-5)$

$-7y=20$

$y=-20/7$

Setting $y=-20/7$ in (1), we get

$x=15+9y=15+9(-20/7)=-75/7$

How do you solve the following system?: x -9y =15, x -2y = -5x−9y=15,x−2y=−5x -9y =15, x -2y = -5