Step 1) Solve the first equation for xx:
x - 4y + color(red)(4y) = 2 + color(red)(4y)x−4y+4y=2+4y
x - 0 = 2 + 4yx−0=2+4y
x = 2 + 4yx=2+4y
Step 2) Substitute (2 + 4y)(2+4y) for xx in the second equation and solve for yy:
3x + 4y = -103x+4y=−10 becomes:
3(2 + 4y) + 4y = -103(2+4y)+4y=−10
(3 xx 2) + (3 xx 4y) + 4y = -10(3×2)+(3×4y)+4y=−10
6 + 12y + 4y = -106+12y+4y=−10
6 + (12 + 4)y = -106+(12+4)y=−10
6 + 16y = -106+16y=−10
6 - color(red)(6) + 16y = -10 - color(red)(6)6−6+16y=−10−6
0 + 16y = -160+16y=−16
16y = -1616y=−16
(16y)/color(red)(16) = -16/color(red)(16)16y16=−1616
(color(red)(cancel(color(black)(16)))y)/cancel(color(red)(16)) = -1
y = -1
Step 3) Substitute -1 for y in the solution to the first equation at the end of Step 1 and calculate x:
x = 2 + 4y becomes:
x = 2 + (4 xx -1)
x = 2 + (-4)
x = 2 - 4
x = -2
The Solution Is:
x = -2 and y = -1
Or
(-2, -1)
