We have, x+y=16x+y=16.............[1][1]
And also 2x+3y=122x+3y=12................[2][2]
From [1][1] subtracting x x from both sides, y=16-xy=16−x and substituting this value for yy into [2][2] we obtain.......
2x+3[16-x]=122x+3[16−x]=12, and so after expanding the bracket we get
2x+48-3x=122x+48−3x=12, after arranging and collecting like terms,
x=36x=36............[3][3] Substitute this value of xx into ..[1][1]
36+y=1636+y=16 and so y=-20y=−20. You can check these answers by
substituting these values of x and yxandy into...... [1][1] or[2][2] and they should satisfy the equations.
