How do you solve #x-3y=7# and #-2x=-6y-17# using substitution?

1 Answer
Jim G.
Mar 15, 2016

system has no solution

Explanation:

Begin by labelling the equations . Makes it 'easier' to follow

x - 3y = 7 ......................................(1)

#-2x = - 6y - 17 ............(2)#

from(1) we obtain x = 7 + 3y and substitute in (2)

hence : -2(7 + 3y) = - 6y - 17

distribute bracket : - 14 - 6y = - 6y - 17

collecting like terms , y terms on left , numbers on right

# -14 - 6y + 6y = - 17" leading to" - 14 = -17#

-14 ≠ - 17 hence system has no solution

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