How do you solve by substitution #3x + 2y = 11# and #x - 2 = -4y#?

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How do you solve by substitution #3x + 2y = 11# and #x - 2 = -4y#?

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Answer 1 · 2018-04-17T21:03:01

#(4,-1/2)#

Explanation:

#3x+2y=11 and x-2 =-4y#
Step 1:Choose an equation #x-2 =-4y#
Step 2: Isolate a variable #x =-4y +2#
Step 3: Substitute #-4y +2# for #x# in the other equation
#3(-4y+2)+2y=11 #
Step 4:Distribute #-12y+6+2y=11 #
Step 5:Simplify #-10y=5#
Step 6: Find #y# value #y=-1/2#
Step 7: Plug y value back into any equation #x-2 =-4(-1/2)#
Step 8:Solve for "x " #x=4#

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How do you solve by substitution #3x + 2y = 11# and #x - 2 = -4y#?

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