How do you solve the following linear system: $2 x + y = - 4, y = - 3 x + 2,$ $2x + y = -4, y = -3x + 2,$ ?

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Answer 1 · 2018-04-22T04:36:19

$x = 6$ $x=6$
$y = - 16$ $y=-16$

Given -

$2 x + y = - 4$ $2x+y=-4$ ---------------- (1)
$y = - 3 x + 2$ $y=-3x+2$ ---------------(2)

Substitute $y = - 3 x + 2$ $y=-3x+2$ in equation (1)

$2 x + (- 3 x + 2) = - 4$ $2x+(-3x+2)=-4$

$2 x - 3 x = 2 = - 4$ $2x-3x=2=-4$

$- x = - 4 - 2 = - 6$ $-x=-4-2=-6$

$x = 6$ $x=6$

Substitute $x = 6$ $x=6$ in equation (2)

$y = - 3 (6) + 2 = - 18 + 2 = - 16$ $y=-3(6)+2=-18+2=-16$

$y = - 16$ $y=-16$

How do you solve the following linear system: 2x+y=−4,y=−3x+2,2x + y = -4, y = -3x + 2, ?