How do you use the substitution method to solve $y=6x+5, 6x-y=7$ ?

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Answer 1 · 2017-01-05T14:45:57

This system has no solutions. See explanation.

The variable $y$ is calculated in the first equation, so we can substitute it to the second:

$6x-(6x+5)=7$

$6x-6x-5=7$

$-5=7$

This equation is false, so the starting system has no solutions.

How do you use the substitution method to solve y=6x+5, 6x-y=7y=6x+5, 6x-y=7?