How do you solve $4x-3y=-19$ and $2x+y=13$ using substitution?

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Answer 1 · 2016-03-13T02:00:35

$x=2$
$y=9$

How do you solve 4x−3y=−19 and 2x+y=13 using substitution?

From the given:
Let $4x−3y=−19" "$ first equation
Let $2x+y=13" "$ second equation

start from second equation

$y=13-2x$ insert this equation into the first equation

$4x−3y=−19" "$ first equation
$4x−3(13-2x)=−19" "$
$4x-39+6x=-19$
$4x+6x=39-19$
$10x=20$
$x=2$

Solve for y using the second equation

$2x+y=13" "$ second equation
$2(2)+y=13" "$
$4+y=13$
$y=13-4$
$y=9$

God bless...I hope the explanation is useful.

How do you solve 4x-3y=-194x-3y=-19 and 2x+y=132x+y=13 using substitution?