How do you solve $2 x + 3 y = 6$ $2x + 3y = 6$ and $x + y = 3$ $x + y = 3$ using substitution?

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How do you solve $2 x + 3 y = 6$ $2x + 3y = 6$ and $x + y = 3$ $x + y = 3$ using substitution?

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Answer 1 · 2018-03-23T14:56:48

$x = 3, y = 0$ $x = 3, y = 0$

Explanation:

$2 x + 3 y = 6$ $2x + 3y = 6$

$x + y = 3$ $x + y = 3$

Let's solve for $x$ $x$ in the second equation

$x = 3 - y$ $x = 3 - y$

Now let's plug $(3 - y)$ $(3-y)$ in for $x$ $x$ in the first equation

$2 (3 - y) + 3 y = 6$ $2(3-y) + 3y = 6$

$6 - 2 y + 3 y = 6$ $6 - 2y + 3y = 6$

$y = 0$ $y = 0$

$\cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot$ $* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *$

Now we have $y$ $y$ , let's find $x$ $x$

$x = 3 - y$ $x = 3 - y$

$x = 3 - 0$ $x = 3 - 0$

$x = 3$ $x = 3$

$\cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot$ $* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *$

Let's double check our work and use our $x$ $x$ and $y$ $y$ values in the first equation and solve it. If our numbers are correct, the equation should equal $6$ $6$

#2(3) + 3(0)

$6 + 0$ $6 + 0$

$6 = 6$ $6 = 6$ ! We were right!

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How do you solve $2 x + 3 y = 6$ $2x + 3y = 6$ and $x + y = 3$ $x + y = 3$ using substitution?

1 Answer

Explanation:

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How do you solve $2 x + 3 y = 6$ $2x + 3y = 6$ and $x + y = 3$ $x + y = 3$ using substitution?