How do you solve the following linear system #2x-3y= 3, x+y=-3 #?

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Answer 1 · 2015-12-29T17:15:30

The solution for the system of equations is:
#color(blue)(x=-6/5#

#color(blue)(y=-9/5#

#color(blue)(2x)-3y=3#......equation #(1)#

#x+y=-3# , multiplying by #2#
#color(blue)(2x)+2y=-6#......equation #(2)#

Solving by elimination.

Subtracting equation #2# from #1#

#color(blue)(2x)-3y=3#

#-color(blue)(2x)-2y=+6#

#-5y=9#

#color(blue)(y=-9/5#

Finding #x# from equation #2#:
#x+y=-3#

#x=-3-y#

#x=-3- (-9/5)#
#x=-3 +9/5#

#x=-15/5 +9/5#

#color(blue)(x=-6/5#