How do you solve $x = - 2 y$ $x=-2y$ and $x = 2 - 4 y$ $x=2-4y$ using the substitution method?

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How do you solve $x = - 2 y$ $x=-2y$ and $x = 2 - 4 y$ $x=2-4y$ using the substitution method?

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Answer 1 · 2018-03-30T09:20:13

$(x, y) \to (- 2, 1)$ $(x,y)to(-2,1)$

Explanation:

$x = - 2 y \to (1)$ $x=-2yto(1)$

$x = 2 - 4 y \to (2)$ $x=2-4yto(2)$

$since both equations express x in terms of y we can$ $"since both equations express x in terms of y we can"$
$equate the right sides$ $"equate the right sides"$

$\Rightarrow - 2 y = 2 - 4 y$ $rArr-2y=2-4y$

$add 4y to both sides$ $"add 4y to both sides"$

$-2y+4y=2cancel(-4y)cancel(+4y)$

$rArr2y=2$

$"divide both sides by 2"$

$rArry=1$

$"substituting "y=1" into equation "(1)" gives x"$

$rArrx=-2xx1=-2$

$"the solution is "(x,y)to(-2,1)$

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How do you solve $x = - 2 y$ $x=-2y$ and $x = 2 - 4 y$ $x=2-4y$ using the substitution method?

1 Answer

Explanation:

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How do you solve x=-2yx=−2yx=-2y and x=2-4yx=2−4yx=2-4y using the substitution method?

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Explanation:

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How do you solve $x = - 2 y$ $x=-2y$ and $x = 2 - 4 y$ $x=2-4y$ using the substitution method?