How do you solve #x=-2y# and #x=2-4y# using the substitution method?
1 Answer
Mar 30, 2018
Explanation:
#x=-2yto(1)#
#x=2-4yto(2)#
#"since both equations express x in terms of y we can"#
#"equate the right sides"#
#rArr-2y=2-4y#
#"add 4y to both sides"#
#-2y+4y=2cancel(-4y)cancel(+4y)#
#rArr2y=2#
#"divide both sides by 2"#
#rArry=1#
#"substituting "y=1" into equation "(1)" gives x"#
#rArrx=-2xx1=-2#
#"the solution is "(x,y)to(-2,1)#
