How do you solve the following system?: # 3x-2y=4 , x-4y=3 #

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How do you solve the following system?: # 3x-2y=4 , x-4y=3 #

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Answer 1 · 2015-11-19T12:56:21

I found:
#x=1#
#y=-1/2#

Explanation:

We can isolate #x# from the second equation and substitute into the first to find #y#:
#x=4y+3#
Into the first:
#3(color(red)(4y+3))-2y=4#
#12y+9-2y=4#
#10y=-5#
#y=-5/10=-1/2#
Use this value back into:
#x=4(color(red)(-1/2))+3=-2+3=1#

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How do you solve the following system?: # 3x-2y=4 , x-4y=3 #

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