How do you solve the system #x+2y=13# and #-2x-3y=-18# using substitution?

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Answer 1 · 2017-08-04T05:56:33

#y=8#
#x=-3#

Given -

#x+2y=13# ------------------- (1)
#-2x-3y=-18# -------------------(2)

Solve equation (1) for #x#

#x=13-2y#

Substitute #x=13-2y# in equation (2)

#-2(13-2y)-3y=-18#
Simplify
#-26+4y-3y=-18#
#y=-18+26=8#

#y=8#

Substitute #y=8# in equation (1)

#x+2(8)=13#
#x+16=13#
#x=13-16=-3#
#x=-3#