How do you solve by substitution $2 x - y = 32$ $2x-y=32$ and $y - 5 x = 13$ $y-5x=13$ ?

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Answer 1 · 2015-07-01T08:11:34

$x = - 15, y = - 62$ $color(blue)(x=-15, y=-62$

$2 x - y = 32$ $2x-y=32$ .........equation $(1)$ $(1)$

$y - 5 x = 13$ $y-5x=13$
$y = 13 + 5 x$ $color(blue)(y=13 + 5x$ ........equation $(2)$ $(2)$

Substituting equation $2$ $2$ in $1$ $1$ to find $x$ $x$ :

$2 x - y = 32$ $2x-y=32$

$2 x - (13 + 5 x) = 32$ $2x-color(blue)((13 + 5x))=32$

$- 3 x = 32 + 13$ $-3x=32 +13$

$- 3 x = 45$ $-3x=45$

$x = - 15$ $color(blue)(x=-15$

Finding $y$ $y$ from equation $2$ $2$
$y = 13 + 5 x$ $y=13 +5x$

$y = 13 - 75$ $y=13 -75$

$y = - 62$ $color(blue)(y = -62$
The solution for the equation is:
$x = - 15, y = - 62$ $color(blue)(x=-15, y=-62$

How do you solve by substitution 2x−y=322x-y=32 and y−5x=13y-5x=13?