How do you solve the following system: $2x-5y=-19, 3x+2y =0$ ?

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Answer 1 · 2015-12-09T21:24:37

$x=-2, y=3$

$2x-5y=-19, 3x+2y=0$

$3x+2y=0$
$3x=-2y+0$
$x=-2/3y$

Plug in $x$ for $2x-5y=-19$

$2(-2/3y)-5y=-19$
$-4/3y-5y=-19$
$-4/3y-15/3y=-19$
$-19/3y=-19$
$3(-19/3y)=3(-19)$
$-19y=-57$
$y=3$

Plug in $y$ in $x=-2/3y$ to get $x$

$x=-2/3(3)$
$x=-2$

$x=-2, y=3$

How do you solve the following system: 2x-5y=-19, 3x+2y =0 2x-5y=-19, 3x+2y =0 ?