How do you solve the following system: #2x-5y=-19, 3x+2y =0 #?

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Answer 1 · 2015-12-09T21:24:37

#x=-2, y=3#

#2x-5y=-19, 3x+2y=0#

#3x+2y=0#
#3x=-2y+0#
#x=-2/3y#

Plug in #x# for #2x-5y=-19#

#2(-2/3y)-5y=-19#
#-4/3y-5y=-19#
#-4/3y-15/3y=-19#
#-19/3y=-19#
#3(-19/3y)=3(-19)#
#-19y=-57#
#y=3#

Plug in #y# in #x=-2/3y# to get #x#

#x=-2/3(3)#
#x=-2#

#x=-2, y=3#