How do you solve the following system of equations? #3x +4y = 15, 3x + 2y = 12#

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Answer 1 · 2018-03-14T02:35:05

#(3,3/2)#

Because we have a #3x# in both equations, we can solve this system using the elimination method.

#3x+4y=15#
#3x+2y=12#

You can subtract the bottom equation from the top one to get:

#2y=3#
#y=3/2#

To solve for #x#, you can plug #y# into one of the equations. In this case, the bottom equation would be easier to use.

#3x+2(3/2)=12#
#3x+3=12#
#3x=9#
#x=3#

#x=3# and #y=3/2#, so the solution to this system is...
#(3,3/2)#