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How do you solve by substitution $5 \frac{x}{3} + \frac{y}{4} = 7$ $5x/3 + y/4 = 7$ and $2 \frac{x}{3} + \frac{y}{8} = 3$ $2x/3 + y/8 =3$ ?

1 Answer

Jun 16, 2015

I found:
$x = 3$ $x=3$
$y = 8$ $y=8$

Explanation:

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