How do you solve the following system: $- 6 x + 5 y = 4, x - 10 y = 10$ $-6x + 5y = 4 , x-10y=10$ ?

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How do you solve the following system: $- 6 x + 5 y = 4, x - 10 y = 10$ $-6x + 5y = 4 , x-10y=10$ ?

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Answer 1 · 2016-01-10T11:26:20

$x = - \frac{18}{11}$ $x=-18/11$ , $y = - \frac{64}{55}$ $y=-64/55$

Explanation:

To solve by elimination you will need to make coefficients of x or y "match" so that when you add or subtract the equations one of the variables will be eliminated.

If we double the first equation we get:

$- 12 x + 10 y = 8$ $-12x + 10y = 8$

$x - 10 y = 10$ $x - 10y = 10$

Now if we add the two new equations, we will eliminate y and will be able to solve an equation in x.

$- 11 x = 18 \Rightarrow x = - \frac{18}{11}$ $-11x = 18 implies x=-18/11$

Substitute this back into one of the original equations to find y.

$- 6 \cdot - \frac{18}{11} + 5 y = 4$ $-6*-18/11 + 5y =4$
$\frac{108}{11} + 5 y = 4$ $108/11 +5y = 4$
$5 y = - \frac{64}{11}$ $5y=-64/11$
$y = - \frac{64}{55}$ $y=-64/55$

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How do you solve the following system: $- 6 x + 5 y = 4, x - 10 y = 10$ $-6x + 5y = 4 , x-10y=10$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve the following system: −6x+5y=4,x−10y=10 -6x + 5y = 4 , x-10y=10 ?

1 Answer

Explanation:

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How do you solve the following system: $- 6 x + 5 y = 4, x - 10 y = 10$ $-6x + 5y = 4 , x-10y=10$ ?