How do you solve $2x-6y=40$ and $7x+60=y$ using substitution?

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Answer 1 · 2016-06-23T10:53:28

$x=-10$ and $y=-10$

As $7x+60=y$ , we can write $2x-6y=40$ by substituting value of $y$ as

$2x-6(7x+60)=40$

or $2x-42x-360=40$

or $-40x=40+360=400$

Hence $x=400/-40=-10$

and $y=7xx(-10)+60=-10$

How do you solve 2x-6y=402x-6y=40 and 7x+60=y7x+60=y using substitution?