What are the solution(s) to the following system of equations y = -x^2y=−x2 and y = x?
1 Answer
Aug 8, 2016
x = 0 , x = - 1
Explanation:
Since we are given 2 values that y equates to we can equate the right sides.
rArrx=-x^2rArrx^2+x=0⇒x=−x2⇒x2+x=0 factorising :
x(x+1)=0x(x+1)=0
rArrx=0" or " x+1=0rArrx=-1⇒x=0 or x+1=0⇒x=−1 The solutions are
x=0,x=-1x=0,x=−1
