How do you solve the following linear system 4x - 3y = -5 , 4x +- 4y = -4 ?

1 Answer

For equations 4x-3y=-5 and 4x+4y=-4, solution (-8/7, 1/7)
For equations 4x-3y=-5 and 4x-4y=-4, solution (-2, -1)

Explanation:

We will use color(blue)("method of elimination of variables")

For equations 4x-3y=-5 and 4x+4y=-4

4x+4y=-4
4x-3y=-5

Perform subtraction to obtain

7y=1

then y=1/7
Using 4x+4y=-4 and y=1/7

We have, 4x+4(1/7)=-4

x+1/7=-1

x=-8/7

For equations 4x-3y=-5 and 4x+4y=-4, solution (-8/7, 1/7)

Again, we will use color(blue)("method of elimination of variables")

For equations 4x-3y=-5 and 4x-4y=-4

4x-4y=-4
4x-3y=-5

Perform subtraction to obtain

y=-1

then y=-1
Using 4x-4y=-4 and y=-1

We have, 4x-4(-1)=-4

x-(-1)=-1

x+1=-1

x=-2

For equations 4x-3y=-5 and 4x-4y=-4, solution (-2, -1)
graph{(4x-3y+5)(4x+4y+4)(4x-4y+4)=0 [-3, 2, -5, 5]}

God bless....I hope the explanation is useful..