How do you solve the following linear system $4x - 3y = -5 , 4x +- 4y = -4$ ?

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Answer 1 · 2016-02-28T04:28:46

For equations $4x-3y=-5$ and $4x+4y=-4$ , solution $(-8/7, 1/7)$
For equations $4x-3y=-5$ and $4x-4y=-4$ , solution $(-2, -1)$

We will use $color(blue)("method of elimination of variables")$

For equations $4x-3y=-5$ and $4x+4y=-4$

$4x+4y=-4$
$4x-3y=-5$

Perform subtraction to obtain

$7y=1$

then $y=1/7$
Using $4x+4y=-4$ and $y=1/7$

We have, $4x+4(1/7)=-4$

$x+1/7=-1$

$x=-8/7$

For equations $4x-3y=-5$ and $4x+4y=-4$ , solution $(-8/7, 1/7)$

Again, we will use $color(blue)("method of elimination of variables")$

For equations $4x-3y=-5$ and $4x-4y=-4$

$4x-4y=-4$
$4x-3y=-5$

Perform subtraction to obtain

$y=-1$

then $y=-1$
Using $4x-4y=-4$ and $y=-1$

We have, $4x-4(-1)=-4$

$x-(-1)=-1$

$x+1=-1$

$x=-2$

For equations $4x-3y=-5$ and $4x-4y=-4$ , solution $(-2, -1)$
graph{(4x-3y+5)(4x+4y+4)(4x-4y+4)=0 [-3, 2, -5, 5]}

God bless....I hope the explanation is useful..

How do you solve the following linear system 4x - 3y = -5 , 4x +- 4y = -4 4x - 3y = -5 , 4x +- 4y = -4 ?