How do you solve $6 y - x = - 36$ $6y - x = -36$ and $y = - 3 x$ $y = -3x$ using substitution?

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How do you solve $6 y - x = - 36$ $6y - x = -36$ and $y = - 3 x$ $y = -3x$ using substitution?

1 Answer

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Answer 1 · 2016-06-05T11:28:52

$x = \frac{36}{19}$ $x=36/19$
$y = - \frac{108}{19}$ $y=-108/19$

Explanation:

if $y = - 3 x$ $y=-3x$ let's substitute in the first equation, so:
$6 (- 3 x) - x = - 36$ $6(-3x)-x=-36$
then
$- 18 x - x = - 36$ $-18x-x=-36$
$- 19 x = - 36$ $-19x=-36$
$x = \frac{36}{19}$ $x=36/19$

and
$y = - 3 (\frac{36}{19})$ $y=-3(36/19)$
$y = - \frac{108}{19}$ $y=-108/19$

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How do you solve $6 y - x = - 36$ $6y - x = -36$ and $y = - 3 x$ $y = -3x$ using substitution?

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Explanation:

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How do you solve 6y - x = -366y−x=−366y - x = -36 and y = -3xy=−3xy = -3x using substitution?

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How do you solve $6 y - x = - 36$ $6y - x = -36$ and $y = - 3 x$ $y = -3x$ using substitution?