How do you solve the following system?: $6 x - 4 y = 3, 6 x + 5 y = 18$ $6x - 4y = 3 , 6x+5y=18$

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Answer 1 · 2018-03-15T10:03:00

x = $\frac{29}{18}$ $29/18$

y = $\frac{5}{3}$ $5/3$

6x - 4y = 3 -------------(1)

6x + 5y = 18 -----------(2)

taking equation (2) - (1), we get

5y - (-4y) = 18 - 3

9y = 15

dividing through by 9 gives,

y = $\frac{5}{3}$ $5/3$

Substituting the value of y into equation (1) gives,

6x - 4 $(\frac{5}{3})$ $(5/3)$ = 3

6x = $\frac{20}{3}$ $20/3$ + 3

6x = $\frac{29}{3}$ $29/3$

Dividing through by 6 gives,

x = $\frac{29}{3}$ $29/3$ $\cdot$ $*$ $\frac{1}{6}$ $1/6$

x = $\frac{29}{18}$ $29/18$

How do you solve the following system?: 6x−4y=3,6x+5y=186x - 4y = 3 , 6x+5y=18