How do solve the following linear system?: $x = y - 11, x - 3 y = 1$ $x= y - 11 , x - 3y = 1$ ?

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Answer 1 · 2015-12-31T21:57:15

$x = - 17$ $x=-17$ and $y = - 6$ $y=-6$

$x = y - 11$ $x=y-11$
$\Rightarrow y - x = 11$ $implies y-x=11$ $.....................(i)$
$x-3y=1$ $.......................(ii)$

By adding $(i)$ and $(ii)$ , we have
$-2y=12$
$implies y=-6$
Put $y=-6$ in $(ii)$
$implies x-3(-6)=1$
$implies x+18=1$
$implies x=-17$

How do solve the following linear system?: x= y - 11 , x - 3y = 1 x=y−11,x−3y=1 x= y - 11 , x - 3y = 1 ?