How do you solve $2x + 3y = 12$ and $x + 4y = 11$ ?

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Answer 1 · 2018-05-28T01:13:28

$x=3, y=2$

Let's start with the second equation and solve for $x$ in terms of $y$ .

We can subtract $4y$ from both sides to get

$color(blue)(x=11-4y)$

We have solved for $x$ in terms of $y$ , so we can plug this into the first equation. We get

$2(11-4y)+3y=12$

Distributing the $2$ , we get

$22-8y+3y=12$

Combining like terms, we get

$22-5y=12$

We can subtract $22$ from both sides to get

$-5y=-10$

Dividing both sides by $-5$ , we get

$y=2$

To completely solve for $x$ , we can go back to the equation I have in blue, and plug in $y=2$ . We get

$x=11-4(2)$

$x=11-8$

$x=3$

Thus, $x=3$ and $y=2$ .

Hope this helps!

How do you solve 2x + 3y = 122x + 3y = 12 and x + 4y = 11x + 4y = 11?