How do you solve the following system?: $x - y = - 6, - 2 x + 3 y = 5$ $x - y = -6, -2x+3y=5$

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Answer 1 · 2015-11-22T01:43:14

I found:
$x = - 13$ $x=-13$
$y = - 7$ $y=-7$

Isolate $x$ $x$ from the first equation and substitute it into the second to find $y$ $y$ as:

$x = y - 6$ $x=y-6$

into the second:

$- 2 (y - 6) + 3 y = 5$ $-2(y-6)+3y=5$

$- 2 y + 12 + 3 y = 5$ $-2y+12+3y=5$
$y = - 7$ $y=-7$

use this value back into the first equation:
$x = - 7 - 6 = - 13$ $x=-7-6=-13$

How do you solve the following system?: x−y=−6,−2x+3y=5 x - y = -6, -2x+3y=5