What are the solution(s) to the following system of equations $y = x^{2}$ $y = x^2$ and y = –x?

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Answer 1 · 2016-07-20T03:21:27

Since $y = x^{2}$ $y = x^2$ and $y = - x$ $y = -x$ :

$x^{2} = - x$ $x^2 = -x$

$x^{2} + x = 0$ $x^2 + x = 0$

$x (x + 1) = 0$ $x(x + 1) = 0$

$x = 0 and - 1$ $x = 0 and -1$

$y = 0^{2} and {(- 1)}^{2} = 0 and 1$ $y = 0^2 and (-1)^2 = 0 and 1$

Hence, the solution set is ${0, 0}$ ${0, 0}$ and ${- 1, 1}$ ${-1, 1}$ .

Hopefully this helps!

What are the solution(s) to the following system of equations y=x2y = x^2 and y = –x?