How do solve the following linear system?: 9 x-6y =3 , 3x + y = -20 ?

1 Answer
Jun 19, 2018

See a solution process below:

Explanation:

Step 1) Solve the second equation for y:

3x + y = -20

3x - color(red)(3x) + y = -color(red)(3x) - 20

0 + y = -3x - 20

y = -3x - 20

Step 2) Substitute (-3x - 20) for y in the first equation and solve for x:

9x - 6y = 3 becomes:

9x - 6(-3x - 20) = 3

9x - (6 xx -3x) - (6 xx -20) = 3

9x - (-18x) - (-120) = 3

9x + 18x + 120 = 3

(9 + 18)x + 120 = 3

27x + 120 = 3

27x + 120 - color(red)(120) = 3 - color(red)(120)

27x + 0 = -117

27x = -117

(27x)/color(red)(27) = -117/color(red)(27)

(color(red)(cancel(color(black)(27)))x)/cancel(color(red)(27)) = -(9 xx 13)/color(red)(9 xx 3)

x = -(color(red)(cancel(color(black)(9))) xx 13)/color(red)(color(black)(cancel(color(red)(9))) xx 3)

x = -13/3

Step 3) Substitute -13/3 for x in the solution to the second equation at the end of Step 1 and calculate y:

y = -3x - 20 becomes:

y = -(3 xx -13/3) - 20

y = -(-13) - 20

y = 13 - 20

y = -7

The Solution Is:

x = -13/3 and y = -7

Or

(-13/3, -7)