How do you solve the following system?: $3x+3y=-21 , 4x-y=-1$

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How do you solve the following system?: $3x+3y=-21 , 4x-y=-1$

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Answer 1 · 2016-03-01T21:00:00

$y=4x+1->3x+3(4x+1)= -21$
$3x+12x+3=-21->15x=-24->x=-8/5, y=-27/5 = {-8/5,-27/5}$

Explanation:

Solve one of the equations for either one of the variables in this case I solved for y. Then substitute it in for y in the other equation and simplify. Once you find the value of x take it and substitute in to the equation for y in the beginning to find its value.

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How do you solve the following system?: $3x+3y=-21 , 4x-y=-1$

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How do you solve the following system?: 3x+3y=-21 , 4x-y=-1 3x+3y=-21 , 4x-y=-1

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How do you solve the following system?: $3x+3y=-21 , 4x-y=-1$