How do you solve the following linear system: 2x−5y=−4,−3x−8y=−1,?

1 Answer
ali ergin
Jul 15, 2016

x=−37
y=−14

Explanation:

2x−5y=−4 (1)
3⋅(2x−5y)=3⋅(−4)
6x−15y=−12

6x=15y−12 (3)

−3x−8y=−1 (2)
2(−3x−8y)=2(−1)
−6x=−16y−2

6x=16y+2 (4)

we can write the equations (3) and (4) as equal

15y−12=16y+2
−12−2=16y−15y
y=−14

now let us use (1) or (2)
2x−5(−14)=−4
2x+70=−4
2x=−70−4
2x=−74
x=−37

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