How do solve the following linear system?: $2 x + 4 y = 8, 2 x - y = 4$ $2x + 4y = 8 , 2x-y=4$ ?

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Answer 1 · 2016-03-10T16:16:23

The solution for the system of equations is:
$x = \frac{12}{5}$ $color(green)(x =12 /5$
$y = \frac{4}{5}$ $color(green)(y=4/5$

$2 x + 4 y = 8$ $color(blue)(2x) +4y=8$ ...........equation $(1)$ $(1)$
$2 x - y = 4$ $color(blue)(2x)-y=4$ ..............equation $(2)$ $(2)$

Solving by elimination:
Subtracting equation $(2)$ $(2)$ from $(1)$ $(1)$ results in elimination of $2 x$ $2x$ :

$cancelcolor(blue)(2x) +4y=8$
$-cancelcolor(blue)(2x) +y= -4$

$5y= 4$

$color(green)(y=4/5$

Finding $x$ from equation $1$ :

$2x +4y=8$

$2x =8 - 4y$

$2x =8 - 4 xx 4/5$

$2x =8 - 16/5$

$2x =40/5 - 16/5$

$2x =24/5$

$x =cancel24/(5 xx cancel2)$

$color(green)(x =12 /5$

How do solve the following linear system?: 2x + 4y = 8 , 2x-y=4 2x+4y=8,2x−y=4 2x + 4y = 8 , 2x-y=4 ?