How do you solve the following linear system: $y - 2 x = - 6, 7 x - y = 3$ $y - 2x = -6 , 7x - y = 3$ ?

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How do you solve the following linear system: $y - 2 x = - 6, 7 x - y = 3$ $y - 2x = -6 , 7x - y = 3$ ?

1 Answer

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Answer 1 · 2018-03-17T13:17:02

$(x, y) = (- \frac{9}{5}, - \frac{48}{5})$ $(x,y) = (-9/5, -48/5)$

Explanation:

$y = 2 x - 6$ $y=2x-6$ solve for y in terms of x
$7 x - (2 x - 6) = 3$ $7x-(2x-6)=3$ plug in above equation to y
$7 x - 2 x + 12 = 3$ $7x-2x+12=3$ distribute
$5 x = - 9$ $5x=-9$ isolate
$x = - \frac{9}{5}$ $x=-9/5$ solve
$y - 2 (- \frac{9}{5}) = - 6$ $y-2(-9/5)=-6$ plug back into original equation
$y + \frac{18}{5} = - 6$ $y+18/5=-6$ multiply
$y = - \frac{48}{5}$ $y=-48/5$ isolate
$(x, y) = (- \frac{9}{5}, - \frac{48}{5})$ $(x,y) = (-9/5, -48/5)$

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How do you solve the following linear system: $y - 2 x = - 6, 7 x - y = 3$ $y - 2x = -6 , 7x - y = 3$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve the following linear system: y−2x=−6,7x−y=3y - 2x = -6 , 7x - y = 3 ?

1 Answer

Explanation:

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Impact of this question

How do you solve the following linear system: $y - 2 x = - 6, 7 x - y = 3$ $y - 2x = -6 , 7x - y = 3$ ?