How do you solve the following system: $3x+2y =0, 7y − 6x − 5 = 0$ ?

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Answer 1 · 2016-04-03T17:12:20

$y = 5/11, x = -10/33$

Rearrange the first equation to give a value of $y$ with respect to $x$ .

$3x + 2y = 0$
$3x = -2y$
$-3/2x = y$

Now substitute your new value of $y$ into the second equation

$7(-3/2x) - 6x - 5 = 0$
$-21/2x - 6x - 5 = 0$
#-33x - 5 = 0

Rearrange and solve for $x$

$-33/2x = 5$
$x = -10/33$

And because we know $y$ with respect to $x$ , we can solve

$y = -3/2x$
$y = -3/2 * -10/33 = 30/66 = 5/11$

Substitute both values into either original equation and check if it's right.

$3x + 2y = 0$
$-30/33 + 10/11 = 0$

It checks out mathematically, so it must be correct.

How do you solve the following system: 3x+2y =0, 7y − 6x − 5 = 0 3x+2y =0, 7y − 6x − 5 = 0 ?